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Made ${(A)=name:=word} (which is an array assignment) not split on

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quoted whitespace, just like the new ${1+"$@"} handling.
This commit is contained in:
Wayne Davison 2006-02-16 19:51:48 +00:00
parent 0dd130df0d
commit 803fa9872f
1 changed files with 10 additions and 14 deletions
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24
Src/subst.c
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@ -2070,27 +2070,23 @@ paramsubst(LinkList l, LinkNode n, char **str, int qt, int ssub)
case '=':
case Equals:
if (vunset) {
int ws = opts[SHWORDSPLIT];
char sav = *idend;
int l;
*idend = '\0';
val = dupstring(s);
/*
* TODO: this is one of those places where I don't
* think we want to do the joining until later on.
* We also need to handle spbreak and spsep at this
* point and unset them.
*/
if (spsep || spbreak || !arrasg)
if (spsep || !arrasg) {
opts[SHWORDSPLIT] = 0;
multsub(&val, 0, NULL, &isarr, NULL);
else
multsub(&val, 0, &aval, &isarr, NULL);
} else {
opts[SHWORDSPLIT] = spbreak;
multsub(&val, spbreak, &aval, &isarr, NULL);
spbreak = 0;
}
opts[SHWORDSPLIT] = ws;
if (arrasg) {
/*
* This is an array assignment in a context
* where we have no syntactic way of finding
* out what an array element is. So we just guess.
*/
/* This is an array assignment. */
char *arr[2], **t, **a, **p;
if (spsep || spbreak) {
aval = sepsplit(val, spsep, 0, 1);