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zsh/Test/D06subscript.ztst

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# Test parameter subscripting.
%prep
s='Twinkle, twinkle, little *, [how] I [wonder] what? You are!'
a=('1' ']' '?' '\2' '\]' '\?' '\\3' '\\]' '\\?' '\\\4' '\\\]' '\\\?')
typeset -g -A A
A=($a)
%test
x=','
print $s[(i)winkle] $s[(I)winkle]
print ${s[(i)You are]} $#s
print ${s[(r)$x,(R)$x]}
0:Scalar pattern subscripts without wildcards
>2 11
>53 60
>, twinkle, little *,
x='*'
print $s[(i)*] $s[(i)\*] $s[(i)$x*] $s[(i)${(q)x}*] $s[(I)$x\*]
print $s[(r)?,(R)\?] $s[(r)\?,(R)?]
print $s[(r)\*,(R)*]
print $s[(r)\],(R)\[]
0:Scalar pattern subscripts with wildcards
>1 26 1 26 26
>Twinkle, twinkle, little *, [how] I [wonder] what? ? You are!
>*, [how] I [wonder] what? You are!
>] I [
print $s[(i)x] : $s[(I)x]
print $s[(r)x] : $s[(R)x]
0:Scalar pattern subscripts that do not match
>61 : 0
>:
print -R $s[$s[(i)\[]] $s[(i)$s[(r)\*]] $s[(i)${(q)s[(r)\]]}]
0:Scalar subscripting using a pattern subscript to get the index
>[ 1 33
print -R $a[(r)?] $a[(R)?]
print $a[(n:2:i)?] $a[(n:2:I)?]
print $a[(i)\?] $a[(I)\?]
print $a[(i)*] $a[(i)\*]
0:Array pattern subscripts
>1 ?
>2 2
>3 3
>1 13
# It'd be nice to do some of the following with (r), but we run into
# limitations of the ztst script parsing of backslashes in the output.
print -R $a[(i)\\\\?] $a[(i)\\\\\?]
print -R $a[(i)\\\\\\\\?] $a[(i)\\\\\\\\\?]
print -R ${a[(i)\\\\\\\\?]} ${a[(i)\\\\\\\\\?]}
print -R "$a[(i)\\\\\\\\?] $a[(i)\\\\\\\\\?]"
print -R $a[(i)\]] $a[(i)\\\\\]] $a[(i)\\\\\\\\\]] $a[(i)\\\\\\\\\\\\\]]
print -R $a[(i)${(q)a[5]}] $a[(i)${(q)a[8]}] $a[(i)${(q)a[11]}]
print -R $a[(i)${a[3]}] $a[(i)${a[6]}] $a[(i)${a[9]}] $a[(i)${a[12]}]
0:Array pattern subscripts with multiple backslashes
>4 6
>7 9
>7 9
>7 9
>2 5 8 11
>5 8 11
>1 3 4 6
print -R $A[1] $A[?] $A[\\\\3] $A[\\\]]
print -R $A[$a[11]]
print -R $A[${(q)a[5]}]
0:Associative array lookup (direct subscripting)
>] \2 \\] \?
>\\\?
>\\\?
# The (o) is necessary here for predictable output ordering
print -R $A[(I)\?] ${(o)A[(I)?]}
print -R $A[(i)\\\\\\\\3]
print -R $A[(I)\\\\\\\\\?] ${(o)A[(I)\\\\\\\\?]}
0:Associative array lookup (pattern subscripting)
>? 1 ?
>\\3
>\\? \\3 \\?
print -R $A[(R)\?] : ${(o)A[(R)?]}
print -R $A[(R)\\\\\?] ${(o)A[(R)\\\\?]} ${(o)A[(R)\\\\\?]}
print -R ${(o)A[(R)\\\\\\\\\]]}
0:Associative array lookup (reverse subscripting)
>: ]
>\? \2 \? \?
>\\]
eval 'A[*]=star'
1:Illegal associative array assignment
?(eval):1: A: attempt to set slice of associative array
x='*'
A[$x]=xstar
A[${(q)x}]=qxstar
print -R ${(k)A[(r)xstar]} $A[$x]
print -R ${(k)A[(r)qxstar]} $A[${(q)x}]
A[(e)*]=star
A[\*]=backstar
print -R ${(k)A[(r)star]} $A[(e)*]
print -R ${(k)A[(r)backstar]} $A[\*]
0:Associative array assignment
>* xstar
>\* qxstar
>* star
>\* backstar
o='['
c=']'
A[\]]=cbrack
A[\[]=obrack
A[\\\[]=backobrack
A[\\\]]=backcbrack
print -R $A[$o] $A[$c] $A[\[] $A[\]] $A[\\\[] $A[\\\]]
print -R $A[(i)\[] $A[(i)\]] $A[(i)\\\\\[] $A[(i)\\\\\]]
0:Associative array keys with open and close brackets
>obrack cbrack obrack cbrack backobrack backcbrack
>[ ] \[ \]
print -R $A[$o] $A[$s[(r)\[]]
print -R $A[(r)$c] $A[(r)$s[(r)\]]]
print -R $A[$A[(i)\\\\\]]]
0:Associative array lookup using a pattern subscript to get the key
>obrack obrack
>] ]
>backcbrack
print -R ${A[${A[(r)\\\\\\\\\]]}]::=zounds}
print -R ${A[${A[(r)\\\\\\\\\]]}]}
print -R $A[\\\\\]]
0:Associative array substitution-assignment with reverse pattern subscript key
>zounds
>zounds
>zounds
print -R ${(o)A[(K)\]]}
print -R ${(o)A[(K)\\\]]}
0:Associative array keys interpreted as patterns
>\2 backcbrack cbrack star
>\\\4 \\\? star zounds
# It doesn't matter which element we get, since we never guarantee
# ordering of an associative array. So just test the number of matches.
array=(${(o)A[(k)\]]})
print ${#array}
array=(${(o)A[(k)\\\]]})
print ${#array}
0:Associative array keys interpreted as patterns, single match
>1
>1
typeset -g "A[one\"two\"three\"quotes]"=QQQ
typeset -g 'A[one\"two\"three\"quotes]'=qqq
print -R "$A[one\"two\"three\"quotes]"
print -R $A[one\"two\"three\"quotes]
A[one"two"three"four"quotes]=QqQq
print -R $A[one"two"three"four"quotes]
print -R $A[$A[(i)one\"two\"three\"quotes]]
print -R "$A[$A[(i)one\"two\"three\"quotes]]"
0:Associative array keys with double quotes
>QQQ
>qqq
>QqQq
>qqq
>QQQ
print ${x::=$A[$A[(i)one\"two\"three\"quotes]]}
print $x
print ${x::="$A[$A[(i)one\"two\"three\"quotes]]"}
print $x
0:More keys with double quotes, used in assignment-expansion
>qqq
>qqq
>QQQ
>QQQ
qqq=lower
QQQ=upper
print ${(P)A[one\"two\"three\"quotes]}
print "${(P)A[$A[(i)one\"two\"three\"quotes]]}"
0:Keys with double quotes and the (P) expansion flag
>lower
>upper
typeset -ga empty
echo X${${empty##*}[-1]}X
0:Negative index applied to substition result from empty array
>XX
print $empty[(i)] $empty[(I)]
0:(i) returns 1 for empty array, (I) returns 0.
>1 0
array=(one two three four)
print X$array[0]X
0:Element zero is empty if KSH_ZERO_SUBSCRIPT is off.
>XX
array[0]=fumble
1:Can't set element zero if KSH_ZERO_SUBSCRIPT is off.
?(eval):1: array: assignment to invalid subscript range
print X$array[(R)notfound]X
0:(R) returns empty if not found if KSH_ZERO_SUBSCRIPT is off.
>XX
setopt KSH_ZERO_SUBSCRIPT
print X$array[0]X
0:Element zero is element one if KSH_ZERO_SUBSCRIPT is on.
>XoneX
array[0]=fimble
print $array
0:Can set element zero if KSH_ZERO_SUBSCRIPT is on.
>fimble two three four
print X$array[(R)notfound]X
0:(R) yuckily returns the first element on failure withe KSH_ZERO_SUBSCRIPT
>XfimbleX
unsetopt KSH_ZERO_SUBSCRIPT
array[(R)notfound,(r)notfound]=(help help here come the seventies retreads)
print $array
0:[(R)notfound,(r)notfound] replaces the whole array
>help help here come the seventies retreads
string="Why, if it isn't Officer Dibble"
print "[${string[0]}][${string[1]}][${string[0,3]}]"
0:String subscripts with KSH_ZERO_SUBSCRIPT unset
>[][W][Why]
setopt KSH_ZERO_SUBSCRIPT
print "[${string[0]}][${string[1]}][${string[0,3]}]"
0:String subscripts with KSH_ZERO_SUBSCRIPT set
>[W][W][Why]
unsetopt KSH_ZERO_SUBSCRIPT
string[0,3]="Goodness"
print $string
0:Assignment to chunk of string ignores element 0
>Goodness, if it isn't Officer Dibble
string[0]=!
1:Can't set only element zero of string
?(eval):1: string: assignment to invalid subscript range
typeset -A assoc=(leader topcat officer dibble sidekick choochoo)
alias myind='echo leader' myletter='echo 1' myletter2='echo 4'
print ${assoc[$(myind)]}
print $assoc[$(myind)]
print ${assoc[$(myind)][$(myletter)]}${assoc[$(myind)][$(myletter2)]}
assoc[$(myind)]='of the gang'
print ${assoc[$(myind)]}
print $assoc[$(myind)]
print $assoc[leader]
0: Parsing subscript with non-trivial tokenisation
>topcat
>topcat
>tc
>of the gang
>of the gang
>of the gang